Factorise:

$a - b - 4 a^{2} + 4 b^{2}$

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Solution

$a - b - 4 a^{2} + 4 b^{2} = a - b - 4 [a^{2} - b^{2}] = (a - b) - 4 (a^{2} - b^{2}) = (a - b) - 4 (a + b) (a - b) = (a - b) [1 - 4 (a + b)] = (a - b) [1 - 4 a - 4 b]$

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Similar questions

a - b - 4 a^{2} + 4 b^{2}

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4 a^{2} - 4 b^{2} + 4 a + 1

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