Factorise :

$a b^{2} + (a - 1) b - 1$

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Solution

$a b^{2} + (a - 1) b - 1 = a b^{2} + a b - b - 1 = a b (b + 1) - 1 (b + 1) = (b + 1) (a b - 1) A n s .$

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Similar questions

a b^{2} + b (a - 1) - 1

a b^{2} + (a - 1) b - 1

{a b}^{2} + (a - 1) b - 1

Factorise : $a b^{2} - (a - c) b - c$

a b^{2} - (a - c) b - c

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