Factorise $a b (a + b)^{2} - 3 a b (a + b)$

(a + b) (a - b) a b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a + b - 5) (2 a + b) (a - b)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a b (a + b) (a + b - 3)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a b (2 a - b) (2 a + b - 6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $a b (a + b) (a + b - 3)$
$a b (a + b)^{2} - 3 a b (a + b)$
$\Rightarrow a b [(a + b)^{2} - 3 (a + b)]$
$\Rightarrow a b (a + b) [a + b - 3]$
$∴ a b (a + b)^{2} - 3 a b (a + b) = a b (a + b) (a + b - 3)$

Suggest Corrections

Similar questions

A B = A

B A = B

Factorise:
$a^{8} - 2 a^{4} b^{4} + b^{8}$

(A + B) (A - B) = A^{2} - B^{2}

(A B A^{- 1})^{2}

3 \times 3

A

n \times n

3 A B A^{- 1} + A = 2 A^{- 1} B A,

Join BYJU'S Learning Program