Factorise: $a b (c^{2} + 1) + c (a^{2} + b^{2})$

(a b + c) (a + b c)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a c + b) (a b + c)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a + b c) (a c + b)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(a + b) (a c + b)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(a + b c) (a c + b)$
$a b (c^{2} + 1) + c (a^{2} + b^{2})$
$= a b c^{2} + a b + c a^{2} + c b^{2}$
$= a b c^{2} + c a^{2} + a b + c b^{2} = a c (b c + a) + b (a + b c)$
$= (a + b c) (a c + b)$

Suggest Corrections

Similar questions

a^{3} + b^{3} + c^{3} - 3 a b c

∣ ∣ ∣ ∣ \begin{matrix} b + c & a - b & a c + a & b - c & b a + b & c - a & c \end{matrix} ∣ ∣ ∣ ∣ =

a + b + c = a b c

\frac{a (b^{2} c^{2} - 1)}{b c + 1} + \frac{b (c^{2} a^{2} - 1)}{c a + 1} + \frac{c (a^{2} b^{2} - 1)}{a b + 1} = 2 a b c

Join BYJU'S Learning Program