wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Factorise ax2y+bxy2+cxyz

A
x(ax+by+cz)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
y(axbycz)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
xy(ax+by+cz)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
xy(a+by+cz)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D xy(ax+by+cz)
We have, ax2y=a×x×x×y
bxy2=b×x×y×y
and, cxyz=c×x×y×z
The three terms have x and y as common factors
ax2y+bxy2+cxyz=(a×x×x×y)+(b×x×y×y)+(c×x×y×z)
=x×y×(a×x+b×y+c×z)
=xy(ax+by+cz)

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Common Factors
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon