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Question

Factorise ax2y+bxy2+cxyz

A
x(ax+by+cz)
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B
y(axbycz)
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C
xy(ax+by+cz)
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D
xy(a+by+cz)
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Solution

The correct option is D xy(ax+by+cz)
We have, ax2y=a×x×x×y
bxy2=b×x×y×y
and, cxyz=c×x×y×z
The three terms have x and y as common factors
ax2y+bxy2+cxyz=(a×x×x×y)+(b×x×y×y)+(c×x×y×z)
=x×y×(a×x+b×y+c×z)
=xy(ax+by+cz)

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