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Question

Factorise : ax3y2+bx2y3+cx2y2z.

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Solution

ax3y2+bx2y3+cx2y2z

Minimum power of x and y present in each term is 2. Hence x2y2 can be taken common.
ax3y2+bx2y3+cx2y2z=x2y2(ax+by+cz)

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