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Question

Factorise: ax²(4a²-3b)x - 12ab

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Solution

x=ax2+(4a2-3b)x-12ab=0

=ax2+4ax2-3bx-12ab=0

=ax(x+4a)-3b(x+4a)=o

=(ax-3b)(x+4a)=o

=ax-3b=0,x+4a=0

=ax=3b,x=-4a

=x=3b/a,x=-4a

hence,x=3b/a or x=-4a.

hope this help u.


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