Factorise by grouping method:

$16 (a + b)^{2} - 4 a - 4 b$

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Solution

16 (a + b)² - 4a - 4b =16 (a + b)² - 4 (a + b)

= 4 (a + b) [4 (a + b) - 1]

= 4 (a + b) (4a + 4b - 1)

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