1
Question
Factorise by splitting the middle term:
9(x−2y)2−4(x−2y)−13
9(x−2y)2−4(x−2y)−13
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Solution
9(x−2y)2−4(x−2y)−13=9(x−2y)2+9(x−2y)−13(x−2y)−13 =9(x−2y)(x−2y+1)−13(x−2y+1) =(x−2y+1)(9x−18y−13)
9(x−2y)2−4(x−2y)−13=9(x−2y)2+9(x−2y)−13(x−2y)−13
=9(x−2y)(x−2y+1)−13(x−2y+1)
=(x−2y+1)(9x−18y−13)
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