Factorise by taking out the common factors:

$x y (3 x^{2} - 2 y^{2}) - y z (2 y^{2} - 3 x^{2}) + z x (15 x^{2} - 10 y^{2})$

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Solution

xy(3x²- 2y²) - yz(2y²- 3x²) + zx(15x²- 10y²)

= xy(3x²- 2y²) + yz(3x²- 2y²) + zx(15x²- 10y²)

= xy(3x²- 2y²) + yz(3x²- 2y²) + 5zx(3x²- 2y²)

= (3x² - 2y²)[xy + yz + 5zx]

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