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Question

Factorise by taking out the common factors :
xy(3x22y2)yz(2y23x2)+zx(15x210y2)

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Solution

xy(3x22y2)yz(2y23x2)+zx(15x210y2)

=xy(3x22y2)+yz(3x22y2)+5zx(3x22y2)

=(3x22y2)(xy+yz+5zx)

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