Factorise by using formula: $(2 x - 3 y)^{2} - 4 y^{2}$

(2 x - y) (x - 5 y)

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(2 x - y) (2 x - 5 y)

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(x - y) (2 x - 5 y)

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(2 x - y) (2 x - y)

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Solution

The correct option is D $(2 x - y) (2 x - 5 y)$
$F a c t o r i z i n g {(2 x - 3 y)}^{2} - {2 y}^{2}, = (2 x - 3 y + 2 y) (2 x - 3 y - 2 y) = (2 x - y) (2 x - 5 y)$
using the identity $(a^{2} - b^{2}) = (a + b) (a - b)$

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