Factorise by using formula: $4 a^{2} - 25$

(2 a + 5) (2 a)

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(2 a + 5) (2 a + 5)

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(2 a - 5) (2 a - 5)

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(2 a + 5) (2 a - 5)

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Solution

The correct option is D $(2 a + 5) (2 a - 5)$
$F a c t o r i z i n g {4 a}^{2} - 25, = (2 a + 5) (2 a - 5)$
using the identity $(a^{2} - b^{2}) = (a + b) (a - b)$

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