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Question

Factorise by using formula: (5a−3b)2−16b2

A
(5a+b)(57b)
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B
(5a+b)(5a7)
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C
(5a+b)(5a7b)
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D
(5+b)(5a7b)
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Solution

The correct option is C (5a+b)(5a7b)
Factorizing(5a3b)2{4(b)}2,=(5a3b+4b)(5a3b4b)=(5a+b)(5a7b)
using the identity (a2b2)=(a+b)(ab)

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