Factorise by using formula: $9 (3 x + 1)^{2} - 4 (x - 1)^{2}$

(11 x + 1) (7 x - 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(11 x - 1) (7 + 5 x)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(11 x - 1) (7 x + 5)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(11 - 1 x) (7 x + 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(11 x - 1) (7 x + 5)$
$F a c t o r i z i n g {{3 (3 x + 1)}}^{2} - {2 (x - 1)}^{2}, = (9 x + 3 + 2 x - 2) (9 x + 3 - 2 x + 2) = (11 x + 1) (7 x + 5)$

Suggest Corrections

Similar questions

(i) x^{2} + 3 x - 40 = 0 (i i) 12 x^{2} - 17 x + 5 = 0 (i i i) 4 x^{2} + 9 = 12 x (i v) 2 x^{2} - 11 x + 5 = 0

lim x \to 1 \frac{3 x^{5} + 5 x^{10} - 7 x^{15}}{11 x^{15} - 13 x^{9} + 17 x^{4}}

x^{2} + 7 x + 6

x^{2} + 11 x + 18

x^{2} + 2 x - 8

x^{2} - 4 x - 5

x^{2} - 8 x + 12

x^{2} - 5 x - 24

6 x^{2} + 17 x + 12

\frac{3 y}{2}

\frac{y + 4}{4}

\frac{y - 2}{4}

Join BYJU'S Learning Program