Factorise by using formula- 6 2-3 2 - 2 1-3 2

Formula a ^ 2 b ^ 2 =(a+b)(a b) Applying the formula, we get ( 6 2 3 #160; ) ^ 2 ( 2 1 3 #160; ) ^ 2 =(6 2 3 +2 1 3 )(6 2 3 2 1 3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Addition and Subtraction of Algebraic Expression

Factorise by ...

Question

Factorise by using formula:

${(6 \frac{2}{3})}^{2} - {(2 \frac{1}{3})}^{2}$

Open in App

Solution

Suggest Corrections

Similar questions

Evaluate : ${(6 \frac{2}{3})}^{2} - {(2 \frac{1}{3})}^{2}$

1^{2} + 2^{2} + 2^{2} = 3^{2}

2^{2} + 3^{2} + 6^{2} = 7^{2}

3^{2} + 4^{2} + 12^{2} = 13^{2}

4^{2} + 5^{2} + 20^{2} = 21^{2}

5^{2} + 6^{2} + 30^{2} = 31^{2}

6^{2} + 7^{2} + 42^{2} = . . .^{2}

1^{2} + 2^{2} + 2^{2} = 3^{2}

2^{2} + 3^{2} + 6^{2} = 7^{2}

3^{2} + 4^{2} + 12^{2} = 13^{2}

4^{2} + 5^{2} +

= 21^{2}

5^{2} +

+ 30^{2} = 31^{2}

6^{2} + 7^{2} +

=

(24 - 21), (46 - 32), (62 - 23), (84 - 24)

x^{2} + y^{2} - 4 x + 6 y + 10 = 0

4 x - 3 y + 8 = 0

Join BYJU'S Learning Program