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Factorisation by Regrouping Terms

Factorise Com...

Question

Factorise Completely : $2 a^{2} - 8 a - 64$

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Solution

$2 a^{2} - 8 a - 64 = 2 [a^{2} - 4 a - 32] = 2 [a^{2} - 8 a + 4 a - 32] = 2 [a (a - 8) + 4 (a - 8)] = 2 [(a - 8) (a + 4)] = 2 (a - 8) (a + 4)$

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Q. State whether True or False.

Factorization of

2 a^{2} - 8 a - 64

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Factorisation by Regrouping Terms

Standard VIII Mathematics

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