Factorise Completely : $5 b^{2} + 45 b + 90$

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Solution

$5 b^{2} + 45 b + 90 = 5 [b^{2} + 9 b + 18] = 5 [b^{2} + 6 b + 3 b + 18] = 5 [b (b + 6) + 3 (b + 6)] = 5 [(b + 6) (b + 3)] = 5 (b + 6) (b + 3)$

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