Factorise : $16 {(a - b)}^{3} - 24 {(a - b)}^{2}$

4 (a - b) (2 a - b - 3)

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8 {(a - b)}^{2} (2 a - 2 b - 3)

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8 (a - b) (2 a - b - 4)

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None of these

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Solution

The correct option is C $8 {(a - b)}^{2} (2 a - 2 b - 3)$
The value of $16 (a - b)^{3} - 24 (a - b)^{2}$ is
$= [8 \times 2 \times (a - b)^{2} (a - b)] - [3 \times 8 \times (a - b)^{2}]$
$= 8 (a - b)^{2} [2 (a - b) - 3]$
$= 8 (a - b)^{2} (2 a - 2 b - 3)$

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Factorise : 8a³ + b³ + 12a²b + 6ab²

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$4 a^{2} + b^{2} + 4 a b + 8 a + 4 b + 4$ =?

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(b) $(2 a - b + 2)^{2}$

(d) None of these

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