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Question

Factorise : 16x22xyy2 The factors are

A
(4+xy)(4+x+y)
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B
(4xy)(4x+y)
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C
(2+x+y)(2xy)
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D
(4+x+y)(4xy)
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Solution

The correct option is D (4+x+y)(4xy)
Given, 16x22xyy2
=42[x2+2xy+y2]
=42(x+y)2
By using a2b2=(a+b)(ab)
42(x+y)2=(4+x+y)(4xy)

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