Factorise $16 x^{4} - y^{4}$

(4 x + y) (4 x - y) (x^{2} + y^{2})

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(2 x + y) (2 x - y) (4 x^{2} + y^{2})

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(x - y) (4 x - y) (x^{2} + y^{2})

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(x - y) (2 x - y) (4 x^{2} + y^{2})

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Solution

The correct option is B $(2 x + y) (2 x - y) (4 x^{2} + y^{2})$
$16 x^{4} - y^{4} = (4 x^{2})^{2} - (y^{2})^{2} = (4 x^{2} - y^{2}) (4 x^{2} + y^{2})$
${(2 x)^{2} - y^{2}} (4 x^{2} + y^{2}) = (2 x + y) (2 x - y) (4 x^{2} + y^{2})$

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