Factorise :

$27 - x^{3} y^{3} + 6 - 2 x y$

(3 - x y) (11 + x^{2} y^{2} + 3 x y)

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(1 - x y) (11 + x^{2} y^{2} + 3 y)

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(3 - x y) (11 + x^{2} y^{2} + 3 y)

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(1 - x y) (11 - x^{2} y^{2} + 3 x y)

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Solution

The correct option is A $(3 - x y) (11 + x^{2} y^{2} + 3 x y)$
$27 - x^{3} y^{3} + 6 - 2 x y$
$= (3)^{3} - (x y)^{3} + 2 (3 - x y)$
$= (3 - x y) (3^{2} + 3 (x y) + (x y)^{2}) + 2 (3 - x y)$
$= (3 - x y) [9 + 3 x y + x^{2} y^{2} + 2]$
$= (3 - x y) [11 + 3 x y + x^{2} y^{2}]$

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Similar questions

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Factorise :27−x3y3+6−2xy

The correct option is A (3−xy)(11+x2y2+3xy) 27−x3y3+6−2xy=(3)3−(xy)3+2(3−xy)=(3−xy)(32+3(xy)+(xy)2)+2(3−xy)=(3−xy)[9+3xy+x2y2+2]=(3−xy)[11+3xy+x2y2]

Factorise :

$27 - x^{3} y^{3} + 6 - 2 x y$

The correct option is A $(3 - x y) (11 + x^{2} y^{2} + 3 x y)$
$27 - x^{3} y^{3} + 6 - 2 x y$
$= (3)^{3} - (x y)^{3} + 2 (3 - x y)$
$= (3 - x y) (3^{2} + 3 (x y) + (x y)^{2}) + 2 (3 - x y)$
$= (3 - x y) [9 + 3 x y + x^{2} y^{2} + 2]$
$= (3 - x y) [11 + 3 x y + x^{2} y^{2}]$