Factorise :

$3 {(2 x - y)}^{3} + 9 {(2 x - y)}^{2}$

3 {(y)}^{2} (x - y + 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 {(2 x - y)}^{2} (2 x - y + 3)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 {(x - y)}^{2} (2 x - y)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 {(2 x + y)}^{2} (2 x - y + 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $3 {(2 x - y)}^{2} (2 x - y + 3)$
$3 {(2 x - y)}^{3} + 9 {(2 x - y)}^{2}$
The term $(2 x - y)^{2}$ is common in both the terms, it can be taken common.
$= 3 (2 x - y)^{2} (2 x - y + 3)$

Suggest Corrections

Similar questions

y = 3^{x}

3^{2 x} + 3^{x} \times 3 ?

x^{3} - 2 x^{2} - x + 2

x^{3} - 3 x^{2} - 9 x - 5

x^{3} + 13 x^{2} + 32 x + 20

2 y^{3} + y^{2} - 2 y - 1

log 2, log 3

log 7

\begin{matrix} 3^{1 - x - y} = 4^{- y} 2^{2 x - 1} = 3^{3 y - 1} \end{matrix}}

\sqrt[3]{32 x^{6} y^{8}}

Join BYJU'S Learning Program