Factorise: $3 a^{2} + 7 a b - 6 b^{2}$

(a - 3 b) (3 a + 2 b)

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(3 a + b) (3 a - 2 b)

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(a + 3 b) (3 a - 2 b)

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(3 a - b) (3 a - 2 b)

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Solution

The correct option is C $(a + 3 b) (3 a - 2 b)$
$3 a^{2} + 7 a b - 6 b^{2} = 3 a^{2} + 9 a b - 2 a b - 6 b^{2}$ $(\frac{S u m = + 7}{P r o d . = - 18})$
$= 3 a (a + 3 b) - 2 b (a + 3 b) = (a + 3 b) (3 a - 2 b)$

Suggest Corrections

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