Factorise $4 a^{2} - 4 a b + b^{2} - 4 x^{2}$ .

(2 a + b + 2 x) (2 a - b - 2 x)

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(2 a - b - 2 x) (2 a - b - 2 x)

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(2 a - b + 2 x) (2 a + b - 2 x)

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(2 a - b + 2 x) (2 a - b - 2 x)

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Solution

The correct option is D $(2 a - b + 2 x) (2 a - b - 2 x)$
$4 a^{2} - 4 a b + b^{2} - 4 x^{2}$
$= (2 a)^{2} - 2 (2 a) b + b^{2} - (2 x)^{2}$
$= (2 a - b)^{2} - (2 x)^{2}$
$= (2 a - b + 2 x) (2 a - b - 2 x)$

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