Factorise $4 m^{3} n^{2} + 12 m^{2} n^{2} + 18 m^{4} n^{3}$

m^{3} n^{3} (m + 3 m n + 4 m^{2} n)

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m^{2} n^{2} (5 m + 2 n + 6 m^{2} n)

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2 m^{2} n^{2} (2 m + 6 + 9 m^{2} n)

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None of these

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Solution

The correct option is C $2 m^{2} n^{2} (2 m + 6 + 9 m^{2} n)$
The factorization of $4 m^{3} n^{2} + 12 m^{2} n^{2} + 18 m^{4} n^{3}$ is
$2 m^{2} n^{2} (2 m + 6 + 9 m^{2} n)$ ....Taking $2 m^{2} n^{2}$ common

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