Factorise: $- 6 a^{2} + 6 c b - 6 c a$

- 6 (a^{2} + c b - c a)

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6 (a^{2} - c b + c a)

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6 (a^{2} + c b + c a)

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- 6 (a^{2} - c b + c a)

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Solution

The correct option is D $- 6 (a^{2} - c b + c a)$
$- 6 a^{2} + 6 c b - 6 c a = (- 6 \times a \times a) + (6 \times c \times b) - (6 \times c \times a)$

$= - 6 (a^{2} - c b + c a)$

Suggest Corrections

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6 a^{2} + 7 a - 5

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$6 a^{2} - a - 15$

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 0 & 0 0 & 1 & 1 0 & - 2 & 4 \end{matrix} ⎤ ⎥ ⎦, I = ⎡ ⎢ ⎣ \begin{matrix} 1 & 0 & 0 0 & 1 & 0 0 & 0 & 1 \end{matrix} ⎤ ⎥ ⎦

A^{- 1} = [\frac{1}{6} (A^{2} + c A + d I)]

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c

d

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