Factorise : $a^{2} + a b + 9 a + 9 b$

(a + b) (b + 9)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a + 1) (a + 9)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a + b) (a + 9)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(a + 9 b) (a + 9)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(a + b) (a + 9)$
$a^{2} + a b + 9 a + 9 b = a (a + b) + 9 (a + b)$
$= (a + b) (a + 9)$

Suggest Corrections

Similar questions

Question 92 (i)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$x^{2} - 9$

Question 92 (xv)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$\frac{x^{3} y}{9} - \frac{x y^{3}}{16}$

Question 92 (xiv)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$\frac{4 x^{2}}{9} - \frac{9 y^{2}}{16}$

Question 92 (xi)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$y^{3} - \frac{y}{9}$

a^{2} + \frac{b^{2}}{4} + \frac{c^{2}}{9} - a b + \frac{b c}{3} - \frac{2}{3} c a

Join BYJU'S Learning Program