Factorise :

$a^{2} + b c - a c - b^{2}$

(a + b) (a + b - c)

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(a b) (a + b - c)

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(a - b) (a + b - c)

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(a - b) (a b - c)

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Solution

The correct option is B $(a - b) (a + b - c)$
$a^{2} + b c - a c - b^{2}$
$= a^{2} - b^{2} + b c - a c$
$= (a + b) (a - b) - c (a - b)$
$= (a - b) (a + b - c)$

Suggest Corrections

Similar questions

\frac{a^{2} - b^{2} - c^{2}}{(a - b) (a - c)} + \frac{b^{2} - c^{2} - a^{2}}{(b - c) (b - a)} + \frac{c^{2} - a^{2} - b^{2}}{(c - a) (c - b)}

\frac{a^{2}}{b c} + \frac{b^{2}}{a c} + \frac{c^{2}}{b a}

A B = A

B A = B

△_{1}, △_{2}

(b, c), (c, a), (a, b)

(a c - b^{2}, a b - c^{2}), (b a - c^{2}, b c - a^{2}), (c b - a^{2}, c a - b^{2})

\frac{△_{1}}{△_{2}} = (a + b + c)^{2}

a, b, c

A, B, C \in R - (0}

a A + b B + c C + \sqrt{(a^{2} + b^{2} + c^{2}) (A^{2} + B^{2} + C^{2})} = 0

\frac{a B}{b A} + \frac{b C}{c B} + \frac{c A}{a C}

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