Factorise: $a^{3} - b^{3} + 4 (a - b)$

(2 a - 3 b) (a^{2} + a b + b^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a + b) (a^{2} + 2 a b + 3 b^{2} + 8)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2 a + 3 b) (a^{2} + a b + b^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a - b) (a^{2} + a b + b^{2} + 4)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $(a - b) (a^{2} + a b + b^{2} + 4)$
The value of $a^{3} - b^{3} + 4 (a - b)$
$= (a - b) (a^{2} + a b + b^{2}) + 4 (a - b)$
$= (a - b) (a^{2} + a b + b^{2} + 4)$
Hence, option D is correct.

Suggest Corrections

Similar questions

8 a^{3} - b^{3} - 4 a x + 2 b x

a^{3} - b^{3}

Question 84 (ix)

Simplify

$(a - b) (a^{2} + b^{2} + a b) - (a + b) (a^{2} + b^{2} - a b)$

Question 84 (ix)

Simplify

$(a - b) (a^{2} + b^{2} + a b) - (a + b) (a^{2} + b^{2} - a b)$

a^{3} - b^{3} = (a - b) (a^{2} + b^{2} + a b)

Join BYJU'S Learning Program