Factorise :

$a - 3 b + a^{3} - 27 b^{3}$

(a + b) (1 + a^{2} + 3 a b + 9 b^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a b) (1 + a^{2} + 3 a b + 9 b^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(a - 3 b) (1 + a^{2} + 3 a b + 9 b^{2})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(a - b) (1 + a^{2} + 3 a b + 9 b^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $(a - 3 b) (1 + a^{2} + 3 a b + 9 b^{2})$
$a - 3 b + a^{3} - 27 b^{3}$
$= (a - 3 b) + (a - 3 b) (a^{2} + 3 a b + 9 b^{2})$
$= (a - 3 b) (1 + a^{2} + 3 a b + 9 b^{2})$

Suggest Corrections