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Question

Factorise: (2xy)214x+7y18

A
(xy9)(2xy2)
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B
(2xy9)(2xy+7)
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C
(xy9)(2xy+7)
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D
(2xy9)(2xy+2)
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Solution

The correct option is D (2xy9)(2xy+2)
(2xy)214x+7y18
=(2xy)27(2xy)18
Let 2xy=a
=a27a18
=a29a+2a18
=a(a9)+2(a9)
=(a9)(a+2)
Putting the value of a,

(2xy9)(2xy+2)

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