Factorization of Expressions Reducible to Difference of Two Squares
Factorise : ...
Question
Factorise :
(x2+y2−z2)2−4x2y2
A
(x+y+z)(x+y−z)(x−y+z)(x−y−z)
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B
(x−y−z)(x+y−z)(2x−y+z)(x−y+3z)
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C
(x+y+z)(x+y−z)(2x−y−2z)(x−2y−z)
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D
(x−y−z)(x+y−z)(x−2y+z)(x+y−z)
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Solution
The correct option is A(x+y+z)(x+y−z)(x−y+z)(x−y−z) (x2+y2−z2)2−4x2y2 =(x2+y2−z2)2−(2xy)2 =(x2+y2−z2+2xy)(x2+y2−z2−2xy) =((x+y)2−z2)((x−y)2−z2) =(x+y+z)(x+y−z)(x−y+z)(x−y−z)