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Question

Factorise :

(x2+y2−z2)2−4x2y2

A
(x+y+z)(x+yz)(xy+z)(xyz)
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B
(xyz)(x+yz)(2xy+z)(xy+3z)
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C
(x+y+z)(x+yz)(2xy2z)(x2yz)
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D
(xyz)(x+yz)(x2y+z)(x+yz)
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Solution

The correct option is A (x+y+z)(x+yz)(xy+z)(xyz)
(x2+y2z2)24x2y2
=(x2+y2z2)2(2xy)2
=(x2+y2z2+2xy)(x2+y2z22xy)
=((x+y)2z2)((xy)2z2)
=(x+y+z)(x+yz)(xy+z)(xyz)

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