Factorise: $m^{2} - 14 m + 13$

(m - 13) (m - 1)

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{(m - 13)}^{2}

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(m + 13) (m - 1)

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(m - 13) (m + 1)

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Solution

The correct option is D $(m - 13) (m - 1)$
$m^{2} - 14 m + 13$
$13$ has its factors $13$ and $1$ whose sum is $14$ .

$∴ m^{2} - 14 m + 13$
$= m^{2} - 13 m - m + 13$
$= m (m - 13) - 1 (m - 13)$
$= (m - 13) (m - 1)$

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