Factorise: $x^{2} + 6 x + 8$

(x + 8) (x + 1)

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(x + 3) (x + 5)

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(x - 4) (x - 2)

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(x + 4) (x + 2)

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Solution

The correct option is B $(x + 4) (x + 2)$
We need to find two integers whose product is $8$ and sum is $6$ .
The factors are $4$ and $2$ .

$∴ x^{2} + 6 x + 8 = x^{2} + 4 x + 2 x + 8$
$= x (x + 4) + 2 (x + 4)$
$= (x + 4) (x + 2)$

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