Factorise - x2-1x2-2-5x-5x-

The correct option is A ( x+1/x ) ( x+1/x 5 ) x^2+1/x^2+2 5x 5/x = ( x+1/x )^2 5 ( x+1/x ) = ( x+1/x ) ( x+1/x 5 ) ...

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Byju's Answer

Standard VIII

Mathematics

Factorisation Using Algebraic Identities

Factorise : ...

Question

Factorise :
$x^{2} + \frac{1}{x^{2}} + 2 - 5 x - \frac{5}{x}$ .

(x + \frac{1}{x}) (x + \frac{1}{x} - 5)

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(1 + x + \frac{1}{x}) (x - \frac{1}{x} - 5)

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(x + \frac{1}{x}) (x + \frac{1}{x} - 3)

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(2 x + \frac{1}{x}) (x + \frac{1}{x} + 3)

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Solution

The correct option is A $(x + \frac{1}{x}) (x + \frac{1}{x} - 5)$
$x^{2} + \frac{1}{x^{2}} + 2 - 5 x - \frac{5}{x}$
$= {(x + \frac{1}{x})}^{2} - 5 (x + \frac{1}{x})$
$= (x + \frac{1}{x}) (x + \frac{1}{x} - 5)$

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Factorise :x2+1x2+2−5x−5x.

The correct option is A (x+1x)(x+1x−5)x2+1x2+2−5x−5x=(x+1x)2−5(x+1x)=(x+1x)(x+1x−5)

Factorise :
$x^{2} + \frac{1}{x^{2}} + 2 - 5 x - \frac{5}{x}$ .

The correct option is A $(x + \frac{1}{x}) (x + \frac{1}{x} - 5)$
$x^{2} + \frac{1}{x^{2}} + 2 - 5 x - \frac{5}{x}$
$= {(x + \frac{1}{x})}^{2} - 5 (x + \frac{1}{x})$
$= (x + \frac{1}{x}) (x + \frac{1}{x} - 5)$