The correct option is A 1/x (x 2 ) ( x^2+2x+4 ) nbsp; x^2 8/x =x^3 8/x =(x 2)(x^2+2x+4)/x ...

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Method of Common Factors

Factorise : ...

Question

Factorise :

$x^{2} - \frac{8}{x}$

\frac{1}{x} (x - 2) (x^{2} + 2 x + 4)

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\frac{3}{x} (x + 2) (x^{2} + 2 x - 4)

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\frac{1}{x} (x - 2) (x^{3} + 2 x + 4)

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\frac{3}{x} (x + 2) (x^{3} + 2 x - 4)

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Solution

The correct option is A $\frac{1}{x} (x - 2) (x^{2} + 2 x + 4)$
$x^{2} - \frac{8}{x}$
$= \frac{x^{3} - 8}{x}$
$= \frac{(x - 2) (x^{2} + 2 x + 4)}{x}$

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