Factorise
$(x - y)^{2} a^{2} + 2 (x - y) (x + y) a b + b^{2} (x + y)^{2}$

(a x - b y) (a x + b y)

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(a x + b y) (b x + a y)

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(a x - a y + b x + b y) (a x - a y + b x + b y)

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(a x + a y + b x + b y) (a x - a y + b x + b y)

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Solution

The correct option is D $(a x - a y + b x + b y) (a x - a y + b x + b y)$
$(x - y)^{2} a^{2} + 2 (x - y) (x + y) a b + b^{2} (x + y)^{2}$ , using the formula a^2 + 2ab + b^2=(a + b)^2
So, $(x - y)^{2} a^{2} + 2 (x - y) (x + y) a b + b^{2} (x + y)^{2}$
${(x - y) a + b (x + y)} {(x - y) a + b (x + y)}$
$(a x - a y + b x + b y) (a x - a y + b x + b y)$
Answer (C) $(a x - a y + b x + b y) (a x - a y + b x + b y)$

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Factorise: $a x + b x + a y + b y$

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