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Question

Factorise each of the following
164a312a+48a2

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Solution

164a312a+48a2
=(1)3(4a)33(1)2(4a)+3(1)(4a)2
Suitable identities is x3y33x2y+3xy2=(xy)3
(1)3(4a)33(1)2(4a)+3(1)(4a)2
=(14a)3


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