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Question

Factorise each of the following:

27y3+125z3​ [ 3 MARKS]

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Solution

Formula: 1 Mark
Application: 2 Marks

27y3+125z3

=(3y)3+(5z)3

Using the identity
x3+y3=(x+y)(x2+y2xy)
=(3y+5z)((3y)2+(5z)2(3y)(5z))

=(3y+5z)(9y2+25z215yz)


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