CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise each of the following:

27y3+125z3​ [ 3 MARKS]

Open in App
Solution

Formula: 1 Mark
Application: 2 Marks

27y3+125z3

=(3y)3+(5z)3

Using the identity
x3+y3=(x+y)(x2+y2xy)
=(3y+5z)((3y)2+(5z)2(3y)(5z))

=(3y+5z)(9y2+25z215yz)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon