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Question

Factorise for a=1,b=1,c=1 in a2(bc)+b2(ca)+c2(ab)

A
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B
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C
1
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D
2
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Solution

The correct option is B 0
We simply substitute a=1,b=1,c=1 in the expression a2(bc)+b2(ca)+c2(ab) as follows:

a2(bc)+b2(ca)+c2(ab)=12(11)+12(11)+12(11)=(1×0)+(1×0)+(1×0)=0+0+0=0

Hence, a2(bc)+b2(ca)+c2(ab)=0 when a=1,b=1,c=1.

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