Question

Factorise $\frac{12x^4+8x^3-2x}{2x}$.

Answer 1

Step I - Let's find the factors of the numerator $12x^4+8x^3-2x$.

Here we can take $2x$ as the common in all the three terms. So we get,

$12x^4+8x^3-2x$ = $2x(6x^3+4x^2-1)$

Step II - Put the factors of the numerator and divide them by their denominator.

$\frac{12x^4+8x^3-2x}{2x}$ = $\frac{2x(6x^3+4x^2-1)}{2x}$

Now, canceling out to $2x$. We get $6x^3+4x^2-1$

Therefore, the factors of $\frac{12x^4+8x^3-2x}{2x}$$=$ $6x^3+4x^2-1$.