Factorise:
8a327−b38
We know a3−b3=(a−b)(a2+ab+b2)8a327−b38=(2a3)3−(b2)3=(2a3−b2)((2a3)2+2a3×b2+(b2)2)=(2a3−b2)(4a29+2ab6+b24)
Factorise each of the following:
(i) (ii)
(iii) (iv)
(v)