Factorise:
(i) $12 x^{2} - 7 x - 1$
(ii) $2 x^{2} + 7 x + 3$
(iii) $6 x^{2} + 5 x - 6$
(iv) $3 x^{2} - x - 4$

Open in App

Solution

(i) $12 x^{2} - 7 x + 1$
$= 12 x^{2} - 4 x - 3 x + 1$
$= 4 x (3 x - 1) - 1 (3 x - 1)$
$= (4 x - 1) (3 x - 1)$

(ii) $2 x^{2} + 7 x + 3$
$= 2 x^{2} + 6 x + x + 3$
$= 2 x (x + 3) + 1 (x + 3)$
$= (2 x + 1) (x + 3)$

(iii) $6 x^{2} + 5 x - 6$
$= 6 x^{2} + 9 x - 4 x - 6$
$= 3 x (2 x + 3) - 2 (2 x + 3)$
$= (3 x - 2) (2 x + 3)$

(iv)) $3 x^{2} - x - 4$
$= 3 x^{2} - 4 x + 3 x - 4$
$= x (3 x - 4) + 1 (3 x - 4)$
$= (3 x - 4) (x + 1)$

Suggest Corrections

Similar questions

Factorise:
(i) $12 x^{2} - 7 x + 1$
(ii) $2 x^{2} + 7 x + 3$
(iii) $6 x^{2} + 5 x - 6$
(iv) $3 x^{2} - x - 4$

12 x^{2} - 7 x + 1

2 x^{2} + 7 x + 3

6 x^{2} + 5 x - 6

3 x^{2} - x - 4

\frac{3 x^{2} - x - 2}{x^{2} - 7 x + 12} \div \frac{3 x^{2} - 7 x - 6}{x^{2} - 4}

\frac{5 x + 20}{7 x + 28}

\frac{x^{3} - 5 x^{2}}{3 x^{3} + 2 x^{4}}

\frac{6 x^{2} - 5 x + 1}{9 x^{2} + 12 x - 5}

\frac{(x - 3) (x^{2} - 5 x + 4)}{(x - 1) (x^{2} - 2 x - 3)}

x^{2} + 9 x + 18

6 x^{2} + 7 x - 3

2 x^{2} - 7 x - 15

84 - 2 r - 2 r^{2}

Join BYJU'S Learning Program