CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorise :

(i) 16a224ab (ii) 15ab220a2b (iii) 12x2y321x3y2

Open in App
Solution

(i) 16a224ab=8a(2a3b) {HCF of 16 and 24=8}(ii) 15ab220a2b=5ab(3b4a) {HCF of 15 and 20=5}(iii) 12x2y321x3y2=3x2y2(4y7x) Ans. {HCF of 12 and 21=3}


flag
Suggest Corrections
thumbs-up
10
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Common Factors
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon