Question

Factorise:
(i) 16a² − 24ab
(ii) 15ab² − 20a²b
(iii) 12x²y³ − 21x³y²

Answer 1

(i) H.C.F. of $16a^2$ and $24ab$ is $8a$.

∴ $16a^2-24ab=8a\left(2a-3b\right)$

(ii) H.C.F. of $15a{b}^2$ and $20a^{2}b$ is $5ab$.

∴ $15a{b}^2-20a^{2}b=5ab\left(3b-4a\right)$

(iii) ​H.C.F. of $12x^2{y}^3$ and $21x^3{y}^2$ is $3x^2{y}^2$.

∴ $12x^2{y}^3-21x^3{y}^2=3x^2{y}^2\left(4y-7x\right)$