Factorise- i-4-3x2-5x-2-3 ii-7-2x2-10x-4-2

(i) 4√(3)x^2+5x 2√(3) = 4 √(3) x^2 +8x 3x 2 √(3) = 4x (√(3) x+2) √(3) (√(3) x +2) = (√(3) x+2)(4x √(3)) (ii) 7√(2)x^2 10x 4√(2) 7 √(2) x^2 14 x+4x ...

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Byju's Answer

Standard X

Mathematics

Factorisation of Quadratic Polynomials

Factorise: i ...

Question

Factorise:

$(i) 4 \sqrt{3} x^{2} + 5 x - 2 \sqrt{3}$

$(i i) 7 \sqrt{2} x^{2} - 10 x - 4 \sqrt{2}$

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Solution

(i) $4 \sqrt{3} x^{2} + 5 x - 2 \sqrt{3} = 4 \sqrt{3} x^{2} + 8 x - 3 x - 2 \sqrt{3} = 4 x (\sqrt{3} x + 2) - \sqrt{3} (\sqrt{3} x + 2) = (\sqrt{3} x + 2) (4 x - \sqrt{3})$

(ii) $7 \sqrt{2} x^{2} - 10 x - 4 \sqrt{2} 7 \sqrt{2} x^{2} - 14 x + 4 x - 4 \sqrt{2} = 7 \sqrt{2} x (x - \sqrt{2}) + 4 (x - \sqrt{2}) = (x - \sqrt{2}) (7 \sqrt{2} x + 4)$

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Similar questions

Factorise:
(i) $12 x^{2} - 7 x + 1$
(ii) $2 x^{2} + 7 x + 3$
(iii) $6 x^{2} + 5 x - 6$
(iv) $3 x^{2} - x - 4$

Q. Solve the following

\begin{matrix} 4 \sqrt{3} x^{2} + 5 x - 2 \sqrt{3} = 0 7 \sqrt{2} x^{2} - 10 x - 4 \sqrt{2} = 0 \end{matrix}

Factorise:

(i) 12x² − 7x + 1 (ii) 2x² + 7x + 3

(iii) 6x² + 5x − 6 (iv) 3x² − x − 4

Q. Factorise:
(i) x(x + 3) + 5(x + 3)
(ii) 5x(x − 4) − 7(x − 4)
(iii) 2m(1 − n) + 3(1 − n)

Find the product: $(2 x^{2} + 3 x - 7) \times (3 x^{2} - 5 x + 4)$

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Factorise: (i) 4√3x2+5x−2√3 (ii) 7√2x2−10x−4√2

(i) 4√3x2+5x−2√3=4√3x2+8x−3x−2√3=4x(√3x+2)−√3(√3x+2)=(√3x+2)(4x−√3) (ii) 7√2x2−10x−4√27√2x2−14x+4x−4√2=7√2x(x−√2)+4(x−√2)=(x−√2)(7√2x+4)

Factorise:

$(i) 4 \sqrt{3} x^{2} + 5 x - 2 \sqrt{3}$

$(i i) 7 \sqrt{2} x^{2} - 10 x - 4 \sqrt{2}$