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Question

Factorise
(i) 4p29q2
(ii) 63a2112b2
(iii) 49x236
(iv) 16x5144x3
(v) (l+m)2(lm)2
(vi) 9x2y216
(vii) (x22xy+y2)z2
(viii) 25a24b2+28bc49c2

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Solution

(i) 4p29q2
=(2p)2(3q)2
=(2p+3q)(2p3q)
(ii) 63a2112b2
=7[(3a)2(4b)2]
=7(3a+4b)(3a4b)
(iii) 49x236
=[(7x)2(6)2]
=(7x6)(7x+6)
(iv) 16x5144x3
=16x3[x232]
=16x3(x3)(x+3)
(v) (l+m)2(lm)2
=2m×2l=4lm
(vi) 9x2y216
=[(3xy)242]
=(3xy4)(3xy+4)
(vii) (x22xy+y2)z2
=[(xy)2z2]
=(xy+z)(xyz)
(viii) 25a24b2+28bc49c2
=(5a)2[(2b7c)2]
=(5a+2b7c)(5a2b+7c)

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