Factorise :
$(i) 7 (2 x + 5) + 3 (2 x + 5)$ $(i i) 5 a (2 x + 3 y) - 2 b (2 x + 3 y)$

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Solution

We have,
$(i) 7 (2 x + 5) + 3 (2 x + 5) = (2 x + 5) (7 + 3)$
[Taking (2x + 5) common]
$= 10 (2 x + 5)$
$(i i) 5 a (2 x + 3 y) - 2 b (2 x + 3 y) = (2 x + 3 y) (5 a - 2 b)$
[Taking (2x + 3y) common]

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